Gọi x_1;x_2;x_3 là các giá giá trị thỏa mãn

$Ta có { }{4}\left({{{3}{x}{-}{5}}}\right){2}{-}{9}\left({{{9}{x}^{2}{-}{25}}}\right){2}$
${=}{0}{4}\left({{{3}{x}{-}{5}}}\right){2}{-}{9}\left[{{\left({{{3}{x}}}\right){2}{-}{5}^{2}}}\right]{2}$
${=}{0}{4}\left({{{3}{x}{-}{5}}}\right){2}{-}{9}\left[{{\left({{{3}{x}{-}{5}}}\right)\left({{{3}{x}{ }{+}{ }{5}}}\right)}}\right]{2}$
${=}{0}{4}\left({{{3}{x}{-}{5}}}\right){2}{-}{9}\left({{{3}{x}{-}{5}}}\right){2}\left({{{3}{x}{+}{5}}}\right){2}$
${=}{0}\left({{{3}{x}{-}{5}}}\right){2}\left[{{{4}{-}\left({{{3}\left({{{3}{x}{+}{5}}}\right)}}\right){2}}}\right]$
${=}{0}\left({{{3}{x}{-}{5}}}\right){2}\left[{{{4}{-}\left({{{3}\left({{{3}{x}{+}{5}}}\right)}}\right){2}}}\right]$
${=}{0}\left({{{3}{x}{-}{5}}}\right){2}\left({{{2}^{2}{-}\left({{{9}{x}{+}{15}}}\right){2}}}\right)$
${=}{0}\left({{{3}{x}{-}{5}}}\right){2}\left({{{2}{ }{+}{ }{9}{x}{ }{+}{ }{15}}}\right)\left({{{2}{ }-{ }{9}{x}{ }-{ }{15}}}\right)$
${=}{0}\left({{{3}{x}{-}{5}}}\right){2}\left({{{9}{x}{ }{+}{ }{17}}}\right)\left({{{-}{9}{x}{ }-{ }{13}}}\right)$
${=}{0}$
Đáp án cần chọn là: C