Este X có CTPT C_4H_8O_2 . Biết X xrightarrow+H_2O, H+ Y_1 + Y_2 Y_1

Từ chuỗi phản ứng → X là $C{H_3}{\rm{COO}}{{\rm{C}}_2}{H_5}$
$C{H_3}{\rm{COO}}{{\rm{C}}_2}{H_5}\,\, + \,{H_2}O\, \mathbin{\lower.3ex\hbox{$\buildrel\textstyle\rightarrow\over {\smash{\leftarrow}\vphantom{_{\vbox to.5ex{\vss}}}}$}} \,C{H_3}{\rm{COOH}}\,{\rm{ + }}\,{{\rm{C}}_2}{H_5}OH$
${C_2}{H_5}OH\, + \,\frac{1}{2}{O_2}\,$ $\xrightarrow{xt, t^o}$ $C{H_3}{\rm{COOH}}$
→ ${Y_2}$ là $C{H_3}{\rm{COOH}}$
${n_{C{H_3}{\rm{COOH}}}} = \,\frac{{12}}{{60}} = 0,2\,mol\, \to {n_{C{H_3}{\rm{COONa}}}} = \,0,2mol$ → m = 41 (g)